2X2+102x+-8=0

Solution for 2X2+102x+-8=0 equation:

2X^2+102X+-8=0

We add all the numbers together, and all the variables

2X^2+102X=0

a = 2; b = 102; c = 0;
Δ = b2-4ac
Δ = 1022-4·2·0
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(102)-102}{2*2}=\frac{-204}{4}
=-51
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(102)+102}{2*2}=\frac{0}{4}
=0
$