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12x^2-46x-70=0
a = 12; b = -46; c = -70;
Δ = b2-4ac
Δ = -462-4·12·(-70)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5476}=74$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-74}{2*12}=\frac{-28}{24} =-1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+74}{2*12}=\frac{120}{24} =5 $
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