x=5((x/2)+1)

Solution for x=5((x/2)+1) equation:

x=5((x/2)+1)

We move all terms to the left:

x-(5((x/2)+1))=0

We add all the numbers together, and all the variables

x-(5((+x/2)+1))=0

We multiply all the terms by the denominator


x*2)+1))-(5((+x=0

We add all the numbers together, and all the variables

x+x*2)+1))-(5((=0

Wy multiply elements

2x^2+x=0

a = 2; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*2}=\frac{-2}{4}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*2}=\frac{0}{4}
=0
$