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g(-5/3)=-5/3
We move all terms to the left:
g(-5/3)-(-5/3)=0
We multiply parentheses
-5g^2-(-5/3)=0
We get rid of parentheses
-5g^2+5/3=0
We multiply all the terms by the denominator
-5g^2*3+5=0
Wy multiply elements
-15g^2+5=0
a = -15; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-15)·5
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{3}}{2*-15}=\frac{0-10\sqrt{3}}{-30} =-\frac{10\sqrt{3}}{-30} =-\frac{\sqrt{3}}{-3} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{3}}{2*-15}=\frac{0+10\sqrt{3}}{-30} =\frac{10\sqrt{3}}{-30} =\frac{\sqrt{3}}{-3} $
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