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2=3x+10x^2
We move all terms to the left:
2-(3x+10x^2)=0
We get rid of parentheses
-10x^2-3x+2=0
a = -10; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·(-10)·2
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{89}}{2*-10}=\frac{3-\sqrt{89}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{89}}{2*-10}=\frac{3+\sqrt{89}}{-20} $
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