12z-4=32-6z

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Solution for 12z-4=32-6z equation: 



12z-4=32-6z

We move all terms to the left:

12z-4-(32-6z)=0

We add all the numbers together, and all the variables

12z-(-6z+32)-4=0

We get rid of parentheses

12z+6z-32-4=0

We add all the numbers together, and all the variables

18z-36=0

We move all terms containing z to the left, all other terms to the right

18z=36

z=36/18

z=2

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