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10x^2=3x+2
We move all terms to the left:
10x^2-(3x+2)=0
We get rid of parentheses
10x^2-3x-2=0
a = 10; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·10·(-2)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{89}}{2*10}=\frac{3-\sqrt{89}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{89}}{2*10}=\frac{3+\sqrt{89}}{20} $
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