2=3(j-6)-7

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Solution for 2=3(j-6)-7 equation: 



2=3(j-6)-7

We move all terms to the left:

2-(3(j-6)-7)=0



We calculate terms in parentheses: -(3(j-6)-7), so:

3(j-6)-7

We multiply parentheses

3j-18-7

We add all the numbers together, and all the variables

3j-25

Back to the equation:

-(3j-25)



We get rid of parentheses

-3j+25+2=0

We add all the numbers together, and all the variables

-3j+27=0

We move all terms containing j to the left, all other terms to the right

-3j=-27

j=-27/-3

j=+9

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