2b+33=7(1+4b)

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Solution for 2b+33=7(1+4b) equation: 



2b+33=7(1+4b)

We move all terms to the left:

2b+33-(7(1+4b))=0

We add all the numbers together, and all the variables

2b-(7(4b+1))+33=0



We calculate terms in parentheses: -(7(4b+1)), so:

7(4b+1)

We multiply parentheses

28b+7

Back to the equation:

-(28b+7)



We get rid of parentheses

2b-28b-7+33=0

We add all the numbers together, and all the variables

-26b+26=0

We move all terms containing b to the left, all other terms to the right

-26b=-26

b=-26/-26

b=1

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