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2=2x^2-4x+4
We move all terms to the left:
2-(2x^2-4x+4)=0
We get rid of parentheses
-2x^2+4x-4+2=0
We add all the numbers together, and all the variables
-2x^2+4x-2=0
a = -2; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·(-2)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-4}{-4}=1$
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