(x+2)2-x2=32

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Solution for (x+2)2-x2=32 equation: 



(x+2)2-x2=32

We move all terms to the left:

(x+2)2-x2-(32)=0

We add all the numbers together, and all the variables

-1x^2+(x+2)2-32=0

We multiply parentheses

-1x^2+2x+4-32=0

We add all the numbers together, and all the variables

-1x^2+2x-28=0

a = -1; b = 2; c = -28;
Δ = b2-4ac
Δ = 22-4·(-1)·(-28)
Δ = -108
Delta is less than zero, so there is no solution for the equation

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