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x/3x=6+2x
We move all terms to the left:
x/3x-(6+2x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x/3x-(2x+6)=0
We get rid of parentheses
x/3x-2x-6=0
We multiply all the terms by the denominator
x-2x*3x-6*3x=0
Wy multiply elements
-6x^2+x-18x=0
We add all the numbers together, and all the variables
-6x^2-17x=0
a = -6; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·(-6)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*-6}=\frac{0}{-12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*-6}=\frac{34}{-12} =-2+5/6 $
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