29=2-3(c-12)

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Solution for 29=2-3(c-12) equation: 



29=2-3(c-12)

We move all terms to the left:

29-(2-3(c-12))=0



We calculate terms in parentheses: -(2-3(c-12)), so:

2-3(c-12)

determiningTheFunctionDomain
-3(c-12)+2

We multiply parentheses

-3c+36+2

We add all the numbers together, and all the variables

-3c+38

Back to the equation:

-(-3c+38)



We get rid of parentheses

3c-38+29=0

We add all the numbers together, and all the variables

3c-9=0

We move all terms containing c to the left, all other terms to the right

3c=9

c=9/3

c=3

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