5(u+2)-4=4(u+3)-u

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Solution for 5(u+2)-4=4(u+3)-u equation: 



5(u+2)-4=4(u+3)-u

We move all terms to the left:

5(u+2)-4-(4(u+3)-u)=0

We multiply parentheses

5u-(4(u+3)-u)+10-4=0



We calculate terms in parentheses: -(4(u+3)-u), so:

4(u+3)-u

We add all the numbers together, and all the variables

-1u+4(u+3)

We multiply parentheses

-1u+4u+12

We add all the numbers together, and all the variables

3u+12

Back to the equation:

-(3u+12)



We add all the numbers together, and all the variables

5u-(3u+12)+6=0

We get rid of parentheses

5u-3u-12+6=0

We add all the numbers together, and all the variables

2u-6=0

We move all terms containing u to the left, all other terms to the right

2u=6

u=6/2

u=3

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