f(2)=4f(2-1)-5

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Solution for f(2)=4f(2-1)-5 equation: 



f(2)=4f(2-1)-5

We move all terms to the left:

f(2)-(4f(2-1)-5)=0

We add all the numbers together, and all the variables

f2-(4f1-5)=0

We add all the numbers together, and all the variables

f^2-(4f1-5)=0

We get rid of parentheses

f^2-4f1+5=0

We add all the numbers together, and all the variables

f^2-4f+5=0

a = 1; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·1·5
Δ = -4
Delta is less than zero, so there is no solution for the equation

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