26=(13(n-1))/3

Solution for 26=(13(n-1))/3 equation:

26=(13(n-1))/3

We move all terms to the left:

26-((13(n-1))/3)=0

We multiply all the terms by the denominator


-((13(n-1))+26*3)=0


We calculate terms in parentheses: -((13(n-1))+26*3), so:

(13(n-1))+26*3

We add all the numbers together, and all the variables

(13(n-1))+78


We calculate terms in parentheses: +(13(n-1)), so:

13(n-1)

We multiply parentheses

13n-13

Back to the equation:

+(13n-13)


We get rid of parentheses

13n-13+78

We add all the numbers together, and all the variables

13n+65

Back to the equation:

-(13n+65)


We get rid of parentheses

-13n-65=0

We move all terms containing n to the left, all other terms to the right

-13n=65

n=65/-13

n=-5