(5x-60)+(3x-80)+(2x+40)=1800

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Solution for (5x-60)+(3x-80)+(2x+40)=1800 equation: 



(5x-60)+(3x-80)+(2x+40)=1800

We move all terms to the left:

(5x-60)+(3x-80)+(2x+40)-(1800)=0

We get rid of parentheses

5x+3x+2x-60-80+40-1800=0

We add all the numbers together, and all the variables

10x-1900=0

We move all terms containing x to the left, all other terms to the right

10x=1900

x=1900/10

x=190

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