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14-x-3x^2=0
We add all the numbers together, and all the variables
-3x^2-1x+14=0
a = -3; b = -1; c = +14;
Δ = b2-4ac
Δ = -12-4·(-3)·14
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-13}{2*-3}=\frac{-12}{-6} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+13}{2*-3}=\frac{14}{-6} =-2+1/3 $
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