If it's not what You are looking for type in the equation solver your own equation and let us solve it.
260=2x+2(2/3x)
We move all terms to the left:
260-(2x+2(2/3x))=0
Domain of the equation: 3x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(2x+2(+2/3x))+260=0
We multiply all the terms by the denominator
-(2x+2(+2+260*3x))=0
We calculate terms in parentheses: -(2x+2(+2+260*3x)), so:We get rid of parentheses
2x+2(+2+260*3x)
We add all the numbers together, and all the variables
2x+2(260*3x+2)
We multiply parentheses
2x+1560x+4
We add all the numbers together, and all the variables
1562x+4
Back to the equation:
-(1562x+4)
-1562x-4=0
We move all terms containing x to the left, all other terms to the right
-1562x=4
x=4/-1562
x=-2/781
| 4x+19=25 | | 55z+24z^2-24=0 | | 4x-50*50=-5*10*10 | | 3x+40*40=2*2*10*10 | | (2y-10)+10=2y | | 8x-3/3x=21 | | 6÷3p+1=9÷5p-3 | | 130=x+2/3x | | 7+2*6=a | | 130=x+(2/3)x | | 6/3p+1=9/5p-3 | | 2x+34*34=18*18 | | (3y+5)+10=2y | | 4-c5=13 | | 3/2x+4/5=5/2x-6 | | 5y+6=-18y | | 260=2(x+(2/3)x) | | H=-4.9t2+42t+70 | | 8/7=u/9 | | 1x/2=-9 | | 1+2x=3(2x+2)-5(x-3) | | 8x-4(4x+8)=0 | | -3(z-4)(-z+2)=0 | | p-2+ 8= 11 | | 1043=x*11+20 | | 3r-17=-1+r | | 22=x+2x+(2+(7x)) | | 2x2-8x-42=0 | | 7x−12=3x | | 4+3n=-10+n | | -10+6t=-5t+4+9t | | y=50(2.5)3 |