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22=x+2x+(2+(7x))
We move all terms to the left:
22-(x+2x+(2+(7x)))=0
We add all the numbers together, and all the variables
-(x+2x+(7x+2))+22=0
We calculate terms in parentheses: -(x+2x+(7x+2)), so:We get rid of parentheses
x+2x+(7x+2)
We add all the numbers together, and all the variables
3x+(7x+2)
We get rid of parentheses
3x+7x+2
We add all the numbers together, and all the variables
10x+2
Back to the equation:
-(10x+2)
-10x-2+22=0
We add all the numbers together, and all the variables
-10x+20=0
We move all terms containing x to the left, all other terms to the right
-10x=-20
x=-20/-10
x=+2
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