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130=x+2/3x
We move all terms to the left:
130-(x+2/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+x+2/3x)+130=0
We get rid of parentheses
-x-2/3x+130=0
We multiply all the terms by the denominator
-x*3x+130*3x-2=0
Wy multiply elements
-3x^2+390x-2=0
a = -3; b = 390; c = -2;
Δ = b2-4ac
Δ = 3902-4·(-3)·(-2)
Δ = 152076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{152076}=\sqrt{4*38019}=\sqrt{4}*\sqrt{38019}=2\sqrt{38019}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(390)-2\sqrt{38019}}{2*-3}=\frac{-390-2\sqrt{38019}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(390)+2\sqrt{38019}}{2*-3}=\frac{-390+2\sqrt{38019}}{-6} $
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