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25x^2-81x+1=0
a = 25; b = -81; c = +1;
Δ = b2-4ac
Δ = -812-4·25·1
Δ = 6461
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-\sqrt{6461}}{2*25}=\frac{81-\sqrt{6461}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+\sqrt{6461}}{2*25}=\frac{81+\sqrt{6461}}{50} $
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