3(x+12)=16(x+1)

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Solution for 3(x+12)=16(x+1) equation: 



3(x+12)=16(x+1)

We move all terms to the left:

3(x+12)-(16(x+1))=0

We multiply parentheses

3x-(16(x+1))+36=0



We calculate terms in parentheses: -(16(x+1)), so:

16(x+1)

We multiply parentheses

16x+16

Back to the equation:

-(16x+16)



We get rid of parentheses

3x-16x-16+36=0

We add all the numbers together, and all the variables

-13x+20=0

We move all terms containing x to the left, all other terms to the right

-13x=-20

x=-20/-13

x=1+7/13

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