2(5x+45)=(3x-19)

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Solution for 2(5x+45)=(3x-19) equation: 



2(5x+45)=(3x-19)

We move all terms to the left:

2(5x+45)-((3x-19))=0

We multiply parentheses

10x-((3x-19))+90=0



We calculate terms in parentheses: -((3x-19)), so:

(3x-19)

We get rid of parentheses

3x-19

Back to the equation:

-(3x-19)



We get rid of parentheses

10x-3x+19+90=0

We add all the numbers together, and all the variables

7x+109=0

We move all terms containing x to the left, all other terms to the right

7x=-109

x=-109/7

x=-15+4/7

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