25-4(3x+5)=7(4x+3)

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Solution for 25-4(3x+5)=7(4x+3) equation: 



25-4(3x+5)=7(4x+3)

We move all terms to the left:

25-4(3x+5)-(7(4x+3))=0

We multiply parentheses

-12x-(7(4x+3))-20+25=0



We calculate terms in parentheses: -(7(4x+3)), so:

7(4x+3)

We multiply parentheses

28x+21

Back to the equation:

-(28x+21)



We add all the numbers together, and all the variables

-12x-(28x+21)+5=0

We get rid of parentheses

-12x-28x-21+5=0

We add all the numbers together, and all the variables

-40x-16=0

We move all terms containing x to the left, all other terms to the right

-40x=16

x=16/-40

x=-2/5

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