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10=-6+2/5x
We move all terms to the left:
10-(-6+2/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(2/5x-6)+10=0
We get rid of parentheses
-2/5x+6+10=0
We multiply all the terms by the denominator
6*5x+10*5x-2=0
Wy multiply elements
30x+50x-2=0
We add all the numbers together, and all the variables
80x-2=0
We move all terms containing x to the left, all other terms to the right
80x=2
x=2/80
x=1/40
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