2x-4x-6x=2x(x-2-3x)

Solution for 2x-4x-6x=2x(x-2-3x) equation:

2x-4x-6x=2x(x-2-3x)

We move all terms to the left:

2x-4x-6x-(2x(x-2-3x))=0

We add all the numbers together, and all the variables

2x-4x-6x-(2x(-2x-2))=0

We add all the numbers together, and all the variables

-8x-(2x(-2x-2))=0


We calculate terms in parentheses: -(2x(-2x-2)), so:

2x(-2x-2)

We multiply parentheses

-4x^2-4x

Back to the equation:

-(-4x^2-4x)


We get rid of parentheses

4x^2+4x-8x=0

We add all the numbers together, and all the variables

4x^2-4x=0

a = 4; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·4·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*4}=\frac{8}{8}
=1
$