25-(2+5y-3(y+2))=-3(2y-5)-(3(y-1)-3y+3)

Solution for 25-(2+5y-3(y+2))=-3(2y-5)-(3(y-1)-3y+3) equation:

25-(2+5y-3(y+2))=-3(2y-5)-(3(y-1)-3y+3)

We move all terms to the left:

25-(2+5y-3(y+2))-(-3(2y-5)-(3(y-1)-3y+3))=0


We calculate terms in parentheses: -(2+5y-3(y+2)), so:

2+5y-3(y+2)

determiningTheFunctionDomain
5y-3(y+2)+2

We multiply parentheses

5y-3y-6+2

We add all the numbers together, and all the variables

2y-4

Back to the equation:

-(2y-4)



We calculate terms in parentheses: -(-3(2y-5)-(3(y-1)-3y+3)), so:

-3(2y-5)-(3(y-1)-3y+3)

We multiply parentheses

-6y-(3(y-1)-3y+3)+15


We calculate terms in parentheses: -(3(y-1)-3y+3), so:

3(y-1)-3y+3

We add all the numbers together, and all the variables

-3y+3(y-1)+3

We multiply parentheses

-3y+3y-3+3

We add all the numbers together, and all the variables



Back to the equation:

-()


We add all the numbers together, and all the variables

-6y

Back to the equation:

-(-6y)


We get rid of parentheses

-2y+6y+4+25=0

We add all the numbers together, and all the variables

4y+29=0

We move all terms containing y to the left, all other terms to the right

4y=-29

y=-29/4

y=-7+1/4