4(2x+3)-5=2(3x-2)+7

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Solution for 4(2x+3)-5=2(3x-2)+7 equation: 



4(2x+3)-5=2(3x-2)+7

We move all terms to the left:

4(2x+3)-5-(2(3x-2)+7)=0

We multiply parentheses

8x-(2(3x-2)+7)+12-5=0



We calculate terms in parentheses: -(2(3x-2)+7), so:

2(3x-2)+7

We multiply parentheses

6x-4+7

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

8x-(6x+3)+7=0

We get rid of parentheses

8x-6x-3+7=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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