4y-7+4(2y+3)=-2(y+1)

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Solution for 4y-7+4(2y+3)=-2(y+1) equation: 



4y-7+4(2y+3)=-2(y+1)

We move all terms to the left:

4y-7+4(2y+3)-(-2(y+1))=0

We multiply parentheses

4y+8y-(-2(y+1))+12-7=0



We calculate terms in parentheses: -(-2(y+1)), so:

-2(y+1)

We multiply parentheses

-2y-2

Back to the equation:

-(-2y-2)



We add all the numbers together, and all the variables

12y-(-2y-2)+5=0

We get rid of parentheses

12y+2y+2+5=0

We add all the numbers together, and all the variables

14y+7=0

We move all terms containing y to the left, all other terms to the right

14y=-7

y=-7/14

y=-1/2

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