25(4y-3)=5(10y-9)

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Solution for 25(4y-3)=5(10y-9) equation: 



25(4y-3)=5(10y-9)

We move all terms to the left:

25(4y-3)-(5(10y-9))=0

We multiply parentheses

100y-(5(10y-9))-75=0



We calculate terms in parentheses: -(5(10y-9)), so:

5(10y-9)

We multiply parentheses

50y-45

Back to the equation:

-(50y-45)



We get rid of parentheses

100y-50y+45-75=0

We add all the numbers together, and all the variables

50y-30=0

We move all terms containing y to the left, all other terms to the right

50y=30

y=30/50

y=3/5

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