23(3d-4)+100=54

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Solution for 23(3d-4)+100=54 equation: 



23(3d-4)+100=54

We move all terms to the left:

23(3d-4)+100-(54)=0

We add all the numbers together, and all the variables

23(3d-4)+46=0

We multiply parentheses

69d-92+46=0

We add all the numbers together, and all the variables

69d-46=0

We move all terms containing d to the left, all other terms to the right

69d=46

d=46/69

d=2/3

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