1/4(2x+1.2)=3(0.7x+3)-5/1=

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Solution for 1/4(2x+1.2)=3(0.7x+3)-5/1= equation: 



1/4(2x+1.2)=3(0.7x+3)-5/1=

We move all terms to the left:

1/4(2x+1.2)-(3(0.7x+3)-5/1)=0



Domain of the equation: 4(2x+1.2)!=0

x∈R



We calculate fractions


()/8x+(-(x-20x2)/8x=0

We add all the numbers together, and all the variables

(-(+x-20x^2)/8x+()/8x=0

We can not solve this equation

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