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21x^2+5x-7=0
a = 21; b = 5; c = -7;
Δ = b2-4ac
Δ = 52-4·21·(-7)
Δ = 613
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{613}}{2*21}=\frac{-5-\sqrt{613}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{613}}{2*21}=\frac{-5+\sqrt{613}}{42} $
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