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21/3y+2=15/y
We move all terms to the left:
21/3y+2-(15/y)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
21/3y-(+15/y)+2=0
We get rid of parentheses
21/3y-15/y+2=0
We calculate fractions
21y/3y^2+(-45y)/3y^2+2=0
We multiply all the terms by the denominator
21y+(-45y)+2*3y^2=0
Wy multiply elements
6y^2+21y+(-45y)=0
We get rid of parentheses
6y^2+21y-45y=0
We add all the numbers together, and all the variables
6y^2-24y=0
a = 6; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·6·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*6}=\frac{0}{12} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*6}=\frac{48}{12} =4 $
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