21+1/5c=25

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Solution for 21+1/5c=25 equation: 



21+1/5c=25

We move all terms to the left:

21+1/5c-(25)=0



Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



We add all the numbers together, and all the variables

1/5c-4=0

We multiply all the terms by the denominator


-4*5c+1=0

Wy multiply elements

-20c+1=0

We move all terms containing c to the left, all other terms to the right

-20c=-1

c=-1/-20

c=1/20

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