10(x+1)=2(2x-5)

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Solution for 10(x+1)=2(2x-5) equation: 



10(x+1)=2(2x-5)

We move all terms to the left:

10(x+1)-(2(2x-5))=0

We multiply parentheses

10x-(2(2x-5))+10=0



We calculate terms in parentheses: -(2(2x-5)), so:

2(2x-5)

We multiply parentheses

4x-10

Back to the equation:

-(4x-10)



We get rid of parentheses

10x-4x+10+10=0

We add all the numbers together, and all the variables

6x+20=0

We move all terms containing x to the left, all other terms to the right

6x=-20

x=-20/6

x=-3+1/3

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