20x2-16x+32=18x2

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Solution for 20x2-16x+32=18x2 equation: 



20x^2-16x+32=18x^2

We move all terms to the left:

20x^2-16x+32-(18x^2)=0

determiningTheFunctionDomain
20x^2-18x^2-16x+32=0

We add all the numbers together, and all the variables

2x^2-16x+32=0

a = 2; b = -16; c = +32;
Δ = b2-4ac
Δ = -162-4·2·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{4}=4$

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