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20x(x+50)=37500
We move all terms to the left:
20x(x+50)-(37500)=0
We multiply parentheses
20x^2+1000x-37500=0
a = 20; b = 1000; c = -37500;
Δ = b2-4ac
Δ = 10002-4·20·(-37500)
Δ = 4000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4000000}=2000$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1000)-2000}{2*20}=\frac{-3000}{40} =-75 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1000)+2000}{2*20}=\frac{1000}{40} =25 $
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