2x-5(4x+42)=20

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Solution for 2x-5(4x+42)=20 equation: 



2x-5(4x+42)=20

We move all terms to the left:

2x-5(4x+42)-(20)=0

We multiply parentheses

2x-20x-210-20=0

We add all the numbers together, and all the variables

-18x-230=0

We move all terms containing x to the left, all other terms to the right

-18x=230

x=230/-18

x=-12+7/9

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