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30c^2+c-20=0
a = 30; b = 1; c = -20;
Δ = b2-4ac
Δ = 12-4·30·(-20)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-49}{2*30}=\frac{-50}{60} =-5/6 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+49}{2*30}=\frac{48}{60} =4/5 $
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