200X2+800x-19200=0

Solution for 200X2+800x-19200=0 equation:

200X^2+800X-19200=0

a = 200; b = 800; c = -19200;
Δ = b2-4ac
Δ = 8002-4·200·(-19200)
Δ = 16000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16000000}=4000$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-4000}{2*200}=\frac{-4800}{400}
=-12
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+4000}{2*200}=\frac{3200}{400}
=8
$