16x2+1=122

Solution for 16x2+1=122 equation:

16x^2+1=122

We move all terms to the left:

16x^2+1-(122)=0

We add all the numbers together, and all the variables

16x^2-121=0

a = 16; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·16·(-121)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*16}=\frac{-88}{32}
=-2+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*16}=\frac{88}{32}
=2+3/4
$