2x2+24x-3456=0

Solution for 2x2+24x-3456=0 equation:

2x^2+24x-3456=0

a = 2; b = 24; c = -3456;
Δ = b2-4ac
Δ = 242-4·2·(-3456)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-168}{2*2}=\frac{-192}{4}
=-48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+168}{2*2}=\frac{144}{4}
=36
$