20(7x+2)-18(3x+4)-5=25(x+5)

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Solution for 20(7x+2)-18(3x+4)-5=25(x+5) equation:



20(7x+2)-18(3x+4)-5=25(x+5)
We move all terms to the left:
20(7x+2)-18(3x+4)-5-(25(x+5))=0
We multiply parentheses
140x-54x-(25(x+5))+40-72-5=0
We calculate terms in parentheses: -(25(x+5)), so:
25(x+5)
We multiply parentheses
25x+125
Back to the equation:
-(25x+125)
We add all the numbers together, and all the variables
86x-(25x+125)-37=0
We get rid of parentheses
86x-25x-125-37=0
We add all the numbers together, and all the variables
61x-162=0
We move all terms containing x to the left, all other terms to the right
61x=162
x=162/61
x=2+40/61

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