4(X-3)-3(x-3)=5(x+2)-9(7-x)+20

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Solution for 4(X-3)-3(x-3)=5(x+2)-9(7-x)+20 equation: 



4(X-3)-3(X-3)=5(X+2)-9(7-X)+20

We move all terms to the left:

4(X-3)-3(X-3)-(5(X+2)-9(7-X)+20)=0

We add all the numbers together, and all the variables

4(X-3)-3(X-3)-(5(X+2)-9(-1X+7)+20)=0

We multiply parentheses

4X-3X-(5(X+2)-9(-1X+7)+20)-12+9=0



We calculate terms in parentheses: -(5(X+2)-9(-1X+7)+20), so:

5(X+2)-9(-1X+7)+20

We multiply parentheses

5X+9X+10-63+20

We add all the numbers together, and all the variables

14X-33

Back to the equation:

-(14X-33)



We add all the numbers together, and all the variables

X-(14X-33)-3=0

We get rid of parentheses

X-14X+33-3=0

We add all the numbers together, and all the variables

-13X+30=0

We move all terms containing X to the left, all other terms to the right

-13X=-30

X=-30/-13

X=2+4/13

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