15=-3(23-x)+3(x-4)

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Solution for 15=-3(23-x)+3(x-4) equation: 



15=-3(23-x)+3(x-4)

We move all terms to the left:

15-(-3(23-x)+3(x-4))=0

We add all the numbers together, and all the variables

-(-3(-1x+23)+3(x-4))+15=0



We calculate terms in parentheses: -(-3(-1x+23)+3(x-4)), so:

-3(-1x+23)+3(x-4)

We multiply parentheses

3x+3x-69-12

We add all the numbers together, and all the variables

6x-81

Back to the equation:

-(6x-81)



We get rid of parentheses

-6x+81+15=0

We add all the numbers together, and all the variables

-6x+96=0

We move all terms containing x to the left, all other terms to the right

-6x=-96

x=-96/-6

x=+16

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