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2/a+3=3/3a-1
We move all terms to the left:
2/a+3-(3/3a-1)=0
Domain of the equation: a!=0
a∈R
Domain of the equation: 3a-1)!=0We get rid of parentheses
a∈R
2/a-3/3a+1+3=0
We calculate fractions
6a/3a^2+(-3a)/3a^2+1+3=0
We add all the numbers together, and all the variables
6a/3a^2+(-3a)/3a^2+4=0
We multiply all the terms by the denominator
6a+(-3a)+4*3a^2=0
Wy multiply elements
12a^2+6a+(-3a)=0
We get rid of parentheses
12a^2+6a-3a=0
We add all the numbers together, and all the variables
12a^2+3a=0
a = 12; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·12·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*12}=\frac{-6}{24} =-1/4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*12}=\frac{0}{24} =0 $
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