6(1+4m)-2m=50

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Solution for 6(1+4m)-2m=50 equation: 



6(1+4m)-2m=50

We move all terms to the left:

6(1+4m)-2m-(50)=0

We add all the numbers together, and all the variables

6(4m+1)-2m-50=0

We add all the numbers together, and all the variables

-2m+6(4m+1)-50=0

We multiply parentheses

-2m+24m+6-50=0

We add all the numbers together, and all the variables

22m-44=0

We move all terms containing m to the left, all other terms to the right

22m=44

m=44/22

m=2

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