10z-5-4z=6(z-5)B

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Solution for 10z-5-4z=6(z-5)B equation: 



10z-5-4z=6(z-5)

We move all terms to the left:

10z-5-4z-(6(z-5))=0

We add all the numbers together, and all the variables

6z-(6(z-5))-5=0



We calculate terms in parentheses: -(6(z-5)), so:

6(z-5)

We multiply parentheses

6z-30

Back to the equation:

-(6z-30)



We get rid of parentheses

6z-6z+30-5=0

We add all the numbers together, and all the variables

25!=0

There is no solution for this equation

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